Find the focus and directrix of the parabola whose rectangular equation is y^2= -12(x-3)

Thank you! That makes a lot of sense. Would there be a way to create a polar equation from that parabola? Would you just plug it into y^2= -4ax?

plug what ?? into y^2= -4ax

I'm not sure. With the info of what the focus and directrix are, would it be possible to create it into a polar equation? Would I have to gain more information to do that?

just plug x = rcos θ and y = rsin θ into the given equation ----> y^2= -12(x-3)

You will get the polar equation.

Got it. Thank you.

to convert any equation in (x,y) to polar form, put x = rcos θ and y = rsin θ

you will get it.

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up