Find the focus and directrix of the parabola whose rectangular equation is y^2= -12(x-3)
Thank you! That makes a lot of sense. Would there be a way to create a polar equation from that parabola? Would you just plug it into y^2= -4ax?
plug what ?? into y^2= -4ax
I'm not sure. With the info of what the focus and directrix are, would it be possible to create it into a polar equation? Would I have to gain more information to do that?
just plug x = rcos θ and y = rsin θ into the given equation ----> y^2= -12(x-3)
You will get the polar equation.
Got it. Thank you.
to convert any equation in (x,y) to polar form, put x = rcos θ and y = rsin θ
you will get it.
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