Rectangular equations....

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Find the focus and directrix of the parabola whose rectangular equation is y^2= -12(x-3)

May 10th, 2015

You can ask back if you have any doubt. I am here.

May 10th, 2015

Thank you! That makes a lot of sense. Would there be a way to create a polar equation from that parabola? Would you just plug it into y^2= -4ax? 

May 10th, 2015

plug what ?? into y^2= -4ax

May 10th, 2015

I'm not sure. With the info of what the focus and directrix are, would it be possible to create it into a polar equation? Would I have to gain more information to do that? 

May 10th, 2015

just plug x = rcos θ and y = rsin θ into the given equation   ----> y^2= -12(x-3)

You will get the polar equation.

May 10th, 2015

Got it. Thank you. 

May 10th, 2015

Got it. Thank you. 

May 10th, 2015

to convert any equation in (x,y) to polar form, put x = rcos θ and y = rsin θ 

you will get it.

May 10th, 2015

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May 10th, 2015
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May 10th, 2015
Oct 17th, 2017
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