To find side a we have to use the The Law of Cosines

a^2 = b^2^{} + c^2− 2bc cosA

a^2 = 16 + 64 - 2*4*8 cos 48

a = 6.1

Now we use the The Law of Sines to find the smaller of the other two angles.

sin B / b = sin A / a

sin B / 4 = sin 48 / 6.1

sin B = 0.487308082280

I am finishing the question, need few more minutes

B = 29 degrees

To find angle C is easy knowing that angles of a triangle add to 180 degrees

C = 180 -29+48 = 103 degrees

Let me know if you have any questions

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