# The analysis of an organic compound showed that it contained 0.150 mol C, 0.105

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

The analysis of an organic compound showed that it contained 0.150 mol C, 0.105 mol H, 0.0300 mol O, and 0.0450 mol N. What would be the subscript on the H in the empirical formula for this compound?

May 11th, 2015

Empirical Formula - A formula that gives the simplest whole-number ratio of atoms in a compound.

the moles of each element are known, a stoichiometric comparison between the elements can be made to determine the empirical formula. This is achieved by dividing through each of the mole quantities by which ever mole quantity is the smallest number of moles. In this example, the smallest mole quantity is either the moles of carbon or moles of Oxygen

0.105/0.0300 = 3.5 C x 2 = 7 C

0.105/0.0300 = 3.5 H x 2 = 7 H

0.0300/0.0300 = 1 O x 2 = 2 O

0.0450/0.0300 = 1.5 N x 2 = 3 N

Multiply by 2 to get whole numbers

Empirical formula is C7 H7 O2 N3

Subscript on H is thus 7

Hope you understand.

May 11th, 2015

...
May 11th, 2015
...
May 11th, 2015
Nov 25th, 2017
check_circle