##### Need help with functions!

 Mathematics Tutor: None Selected Time limit: 1 Day

Given the following function f(x) = e^x ---> x<0 ; 6 ----x=0 ; cos x-----x > 0

And lim f(x) as x approaches zero...I get that the answer is 1, but where does that come from??

May 12th, 2015

because e^0 = 1  any number to the zero power equal 1

for cosx,  cos0 = 1

May 12th, 2015

But if it is as x is approaching zero, and the question says that 6 is when x=0, why wouldn't it just be 6? There were a couple previous problems to this, stating as x approaches 0 (negative), and I knew that'd be 1, and when x approaches 0 (positive), that'd be 1 as well because of plugging it into where x is < or > than 0, but if it's just 0, why wouldn't it be 6?

May 12th, 2015

because it's only 6 when x is EXACTLY zero, not when it approaches zero.  The graph JUMPS to point 6 ONLY at x = 0, but it approaches 1 from the left and right.

May 12th, 2015

Ah, I gotcha. Thanks

May 12th, 2015

you're welcome :)

May 12th, 2015

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May 12th, 2015
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May 12th, 2015
May 27th, 2017
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