Write the equation of the line through the point (5,5) and perpendicular to y= -6x+1
the product of slopes of perpendicular lines is -1
Assume m is the slope of perpendicular line
then m*(-6) = -1
m = 1/6
so required equation of line will be of the form
y = (1/6)*x + C
now put (5,5) in above equation
5 = 5/6 + C
C = 25/6
therefore required equation of the line is
Y = x/6 + 25/6
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