Help solve this math problem please.

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A cube has a surface area of 216 square cm. A second cube has edges that are 3  times as long. How much greater is the surface area of the second cube than the first cube?

May 12th, 2015

since the cube has six sides, each side has a surface area of 216 / 6 = 36  which means each edge is the square root of 36 which is 6cm

The second cube has edges 3 times as long which means 6x3 = 18 cm

That means each face has an area of 18^2 = 324

And the total surface area is 324x6 = 1944 square cm

1944 / 216 = 9  which means the second cube has a surface area NINE TIMES greater than the first.

May 12th, 2015

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May 12th, 2015
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May 12th, 2015
Oct 23rd, 2017
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