Work done on an object

Science
Tutor: None Selected Time limit: 1 Day

A person applies a constant force on an object of mass 20 kg that causes the object to move horizontally at a constant speed of 0.20 m/s through a distance of 0.80 m. What is the work done on the object?

May 12th, 2015

So the formula to calculate work done on an object through kinematic energy (energy of movement) is force multiplied by distance. Force is mass times acceleration, so multiply 20kg by the acceleration of the object. I'm not sure if you made a typo, but if it is a constant speed there is no acceleration and thus no force, meaning no work was done on the object. If it is constant acceleration then it would be 20kg times 0.2 m/s^2 times 0.8m = 3.2 joules. Let me know if you have any questions.

May 12th, 2015

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May 12th, 2015
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May 12th, 2015
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