A rectangular lot whose perimeter is 330ft is fenced along three sides. An expensive fencing along the lot's length cost $18 per foot. An inexpensive fencing along the two sides widths cost only $3 per foot. The total cost of the fencing along the three sides comes to $2430. What are the lot's dimensions?
To find this answer you have to set two different equations. One for the dimensions of the lot which would be 2x + 2y = 330ft, and the other is for the amount of fencing based on the money. If we use $3 for x side and then $18 for y side then the equation is 6x + 18y = 2430.
You can substitute a variable into the other equation. Solve the first equation for x and plug it into the second. This will give you a value for y that you can plug into the first equation and solve for the dimensions.
The answer is 45ft by 120ft where the 45ft is $3 for each 45 side and the 120ft is $18 fencing for one side.
I'm sorry my answer is short- I was in the process of typing you a more detailed answer and my computer crashed. Please let me know if you would like a further explaination step by step to solve this probelm. I do not mind at all.