the domains of f(x)=1/x is x =/=0 so : Df=IR-{ 0 }

the domains of g(x)=x + 3 so is a polynome so : Dg=IR

the domains of f°g(x) = f(g(x)) = 1/(x+3) so is x + 3 =/=0 so x =/= -3 so : Df°g = IR - {-3}

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