1) 13^0 a) -1 b)13 c)1 d) 0

2) -14^0 a) -14 b)1 c)-1 d)0

3) (-3)^0 a) 0 b)3 c)-1 d)1

4) 5^0 + 12^0 a)17 b)0 c)2 d)1

5) -7(7^0) + (-10)^0 a)1 b)0 c)-2 d)-3

5)

Anything to the 0 power will always be equal to 1.

1) The answer is C

2) The answer is B

3) The answer is D

4) 1+1 = 2 The answer is C

5) -7(1) + 1 = -7 +1 = -6 The answer is ... I'm sorry is there a typo in problem 5? None of the answers are correct.

I hope this helps! Please feel free to contact me with any questions.

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