Find the indicated limit...

Calculus
Tutor: None Selected Time limit: 1 Day

May 12th, 2015

for t>1

sqrt((t+9)(t-1)^2)=(t-1)*sqrt(t+9)

so for t>1 your function equal sqrt(t+9)/7 (simplify by t+1)

Thus the limit is sqrt(10)/7

May 12th, 2015

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May 12th, 2015
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May 12th, 2015
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