In a sample of 80 Americans, 65% wished that they were rich. In a sample of 90 Europeans, 70% wished that they were rich. Find the 99% confidence interval for the difference of the two proportions.
Americans 80 * 0.65 = 56
Europeans 90* 0.7= 63
total sample is 170 and selected 119
potion that is rich is 70% of both the Americans and Europeans.
99% halved is 0.445 on the t table it yields approximately 1.96
mean is 119 and margin of error is 1.96*0.99
the propotional interval is 119 - 1.9404=120.9404 or 119+1.94.4 =117.0496
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