math help please help me

label Calculus
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May 13th, 2015


Standard form :  f(x) = ax^2 +bx+c

     x^2 + 8x + 12 = 0

  (x+2)(x+6)=0; 

   solve for x ,   x= -2,-6

first convert the standard form into vertex form

Vertex form :  f(x)= a(x-h)^2+k

 h  = -b/2a

                       k = f(h)

  h = -8 / (2*1) = -4

  k = f(-4) =  (-4)^2 + 8*(-4) + 12 = 

     = 16 -32+12 = -4

f(x) = (x-(-4))^2 -4

f(x) = (x+4)^2 -4




May 13th, 2015

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