#42 02.05a Fundamental Theorem of Algebra

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May 13th, 2015

x^3 + x^2 + 9x + 9

given zero is 3i

therefore, -3i must be another zero

then, (x+3i)(x-3i) = x^2+9

x^3 + x^2 + 9x + 9 / x^2+9

= x+1

therefore, another zero is -1

So, all the zeros are

-1, -3i, 3i

May 13th, 2015

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May 13th, 2015
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May 13th, 2015
Sep 23rd, 2017
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