You draw nine cards from a standard deck of cards. What is the probability that (A.) four or more will be red (B). exactly two or three will be red (C). two or fewer will be red, and (D). exactly five will be red?

You draw nine cards from a standard deck of cards. What is the probability that

(A.) four or more will be red

(B). exactly two or three will be red

(C). two or fewer will be red, and

(D). exactly five will be red?

iam solving this in a minute...please be patient

ok! Thanks

(A.) four or more will be red=1-26/52*25/51*24/50*23/49=1-0.06=0.94

(B). exactly two or three will be red = probability of getting two reds is 26/52*25/51=0.5*0.49=0.245

probability of getting 3 reds=26/52*25/51*24/50*23/49=0.1176

therefore the probability of getting two or three reds =0.245+0.1176=0.3626

(C). two or fewer will be red,26/52*25/51+26/52=0.245+0.5=0.745

(D). exactly five will be red?= 26/52*25/51*24/50*23/49 *22/48= 0.5*0.49*0.48*0.47*0.46=0.03

the probability that five will be red is 0.03

thank you for your patience.

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