When 32.4 g of water vapor condenses, how much heat is given off? The heat of vaporization for water is 40.67 kJ/mol.
Heat released by condensation of water = No of moles of water x Heat of vaporization of water.
Moles of water = mass of water divided by its molar mass.
Mass of water = 32.4 grams,
molar mass of H20 = 2(1) + 16 = 18 grams
Moles of water = 32.4/18 = 1.8 moles
Heat of vaporization of water = 40.67 kJ/mol
So heat released = (1.8 x 40.67) kJ/mol
= 73.206 kJ.
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