Select the correct net-ionic equation from for each of the reactions, in aqueo

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Sn2+(aq) oxidizes Ni(s)

Co2+(aq) oxidizes Fe(s)

Ni2+(aq) oxidizes Cd(s)


Calculate the standard cell potential for

Ags | Ag+aq || Fe2+aq | Fes

if the standard electrode reduction potentials are

Ag+aq | Ags = 0.799 V Fe2+aq | Fes = -0.409 V

Zn + NiCl2 → ZnCl2 + Ni

Cl2 + H2O → H+ + Cl + HOCl 

Cu(OH)2 + 2HCl → CuCl2 + 2H2

 Ca+ 2HCl → CaCl2 + H2

H+ + HS → H2S

 NiCl2

 NaBr
 AgNO3 
 HNO3
 HBr

 The Cu atom in CuSO4 

The N atom in NO2 
The P atom in PF5 

 The Fe atom in FeO 

May 14th, 2015

Ni0(s) --------- Ni2+ + 2e-

Sn2+ + 2e- ------- Sn0(s) 

Fe0(S) ---------- Fe2+ + 2e-

Co2+ + 2e- ------- Co0(s)

Cd0(s) -------- Cd2+ + 2e-

Ni2+ + 2e- -------- Ni0(s)

2Ag0(S) -------- 2Ag+ + 2e-  E0 = -0.799v

Fe2+ + 2e- -------- Fe0(s)  E0 = -0.409v

NET EQUATION

  2Ag0(S) +Fe2+ ----------  2Ag+ + Fe0(s)  E0 = -1.208v

 NiCl2: Ni= +2 Cl= -1

 NaBr: Na =+1 Br = -1 AgNO3: Ag = +1 NO3 = -1  HNO3: H= +1 NO3 = -1  HBr : H= +1 Br = -1

 The Cu atom in CuSO4 : Cu= +2

The N atom in NO2 : N= +4The P atom in PF5 : P= +5

 The Fe atom in FeO: Fe= +2

Zn + NiCl2 → ZnCl2 + Ni (redox reaction)

Cl2 + H2O → H+ + Cl + HOCl (redox reaction)

Cu(OH)2 + 2HCl → CuCl2 + 2H2O (not redox reaction)

  Ca+ 2HCl → CaCl2 + H2(redox reaction)

H+ + HS → H2S (not redox reaction)


May 14th, 2015

A.  Fe(s) + Co2+(aq) + 2H+(aq)   ___________> Fe2+(aq) + Co(s) + H2(g)
B.  Sn(s) + Ni2+(aq)  ________________>Sn2+(aq) + Ni(s)
C.  Sn2+(aq) + Ni(s)  ________________> Sn(s) + Ni2+(aq)
D.  Co2+(aq) + Fe(s)  _________> Fe2+(aq) + Co(s)
E.  Fe2+(aq) + Co(s) _________________> Co2+(aq) + Fe(s)
F.  Cd(s) + Ni2+(aq)  ____________________>Cd+(aq) + Ni+(aq)
G.  Ni2+(aq) + Cd(s) ______________________> Ni(s) + Cd2+(aq)
H.  Ni2+(aq) + Sn(s)  __________________? Sn2+(aq) + Ni(s)
I.  Ni(s) + Sn2+(aq) + H2O(l)  _____________> Ni2+(aq) + Sn(s) + H2(g) + 2OH-(aq)

May 14th, 2015

those are the options of the net ionic equation

May 14th, 2015

option I for equation 1

option A for equation 2

option F for equation 3

May 14th, 2015

hello

May 14th, 2015

hi

May 14th, 2015

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