A mass of 40.0 grams is attached to a vertical spring with a spring constant k = 20.0 N/m and lowered slowly until the spring stops stretching. How much does the spring stretch?
This is a problem of forces and not of energy because the weight is lowered slowly. k*x = m*g which gives x = 40*10^-3 * 9.8 / 20 = 0.0196 m
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?