##### 14&16.

 Mathematics Tutor: None Selected Time limit: 1 Day

May 14th, 2015

14). Surface Area for a cylinder is 2*pi*radius^2 + 2*pi*radius*x  So for this problem all you need to do is set that equation equal to the S given which is 1097 m^2 and then plug in the given radius, which is 8.2 m, and the only unknown variable is the x variable.

1097 = 2*(3.14)*(8.2)^2 + 2*(3.14)*(8.2)*x

x = 13.1 m

(The two parts of the equation are the surface area of the circles and the surface area of the band in between them)

16). This problem looks basically the same as the picture from problem 15. Using Pythagorean theorem you can find that the other side of the right base "h" is 12 units long. So you use the area of a triangle, multiply that by 2, then add on the three rectangles that are between the two triangles.

(1/2)*base*h*2 + base*height + h*height + hypotenuse*height

(1/2)*9*12*2 + 9*8 + 12*8 + 15*8

108 + 72 + 96 + 120 = 396

So the Surface Area is 396 units^2

(For the drawing just look at the picture from problem 15 and use that since its a triangular prism with a right triangle base)

May 14th, 2015

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May 14th, 2015
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May 14th, 2015
Dec 3rd, 2016
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