22&24.

Mathematics
Tutor: None Selected Time limit: 1 Day

May 14th, 2015

22. First find the surface area of the cone on top. The formula is 3.14(r^2)+3.14*r*l. r=5. l=sqrt(5^2+4^2)=6.40. So plugging r and l into the formula 3.14(r^2)+3.14*r*l, you get 171.98 cm^2. Then find the surface area of the cylinder. The formula is 2*3.14(r^2)+2*3.14*r*h. r=5 and h=12. So plugging r and h into the formula 2*3.14(r^2)+2*3.14*r*h, you get 534.07 cm^2. Then add the two surface areas together: 171.98+534.07=706.05 cm^2.

24. Find the surface are of the top cone. The formula is 3.14(r^2)+3.14*r*l. r=3. l=sqrt(3^2+4^2)=5. So plugging r and l into the formula 3.14(r^2)+3.14*r*l, you get 75.40 cm^2. For the bottom cone, r=3 and l=sqrt(3^2+8^2)=8.54. So plugging r and l into the formula 3.14(r^2)+3.14*r*l, you get 108.76 cm^2. Then add the two surface areas together: 75.40+108.76=184.16 cm^2.


Good luck!

May 14th, 2015

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