Since a point on the unit circle that corresponds to a value of t is: (cos t, sin t), the required point is: y = sin t = sin (11*pi/6 )

x = cos t = cos (11*pi/6)

therefore point (x,y) will be

(cos 11π/6, sin 11π/6) = (√3/2, -1/2).

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up