#12 4.01 questions Precalculus

label Mathematics
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May 14th, 2015

Since a point on the unit circle that corresponds to a value of t is:
(cos t, sin t),

the required point is: y = sin t = sin (11*pi/6 )

x = cos t = cos (11*pi/6)

therefore point (x,y) will be

(cos 11π/6, sin 11π/6) = (√3/2, -1/2).

May 14th, 2015

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May 14th, 2015
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May 14th, 2015
Jun 28th, 2017
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