A bus was purchased for $80,000. Assuming the bus depreciates at a rate of $5,000 per year (straight-line depreciation) for the first 10 years, write the value v of the bus as a function of the time t (measured in years) for 0 ≤ t ≤ 10.

Value of bus after 1 year = $80000 - $5000 x 1 = $ 75000

Value of bus after 2 year = $80000 - $5000 x 2 = $ 70000

Similarly

Value of bus after t years,v = $80000 - $5000 x t (where 0 ≤ t ≤ 10)

You can find the value of bus after any year between 0 to 10 by substituting value of t

Such as Value of 10 yrs = 80000- 5000 *10 = 80000-50000 = $ 30000

Hence Answer : v = $80000 - $5000 x t

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