Since x(t) is an even signal, it is convenient to select the integration interval from –T/2 to

T/2. Equation (5) evaluated for h = 0 yields

p

T

AT

Adt

dt

t

x

c

=

∫

−

2

0

)

(

1

The term c

represents the average value (dc component) of the signal x(t). For h

≠

0 we

have,

,...

,

sin(

±

k

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