Eyjafjallajokull is a volcano in Iceland During a recent eruption, the volcano spewed out copious amounts of ash

timer Asked: Dec 14th, 2017
account_balance_wallet $15

Question description

E is a volcano. During a recent eruption, the volcano spewed copious amounts of ash. One small piece of ash was ejected from the volcano with an initial velocity of 368 ft/sec. The height H, in feet, of our ash projectile is given by the equation:

H = -16t^2 + 368t,

Where t is the time in seconds. The graph of this equation will be a parabola. We will assume that the volcano has no height. In other words, when H=0 at t=0.

Question 1. When does the ash projectile reach the its maximum height? t=?

Question 2. What is its maximum height?

Question 3. When does the ash projectile return to the ground?

Tutor Answer

Borys S
School: UC Berkeley

The solution is ready, please ask if something is unclear.docx and pdf files are identical

Note that H(t)=16t(-t+23) because 368=16*23.
1. The maximum of a parabola branches down is reached at t=-b/(2a), where a=-16...

flag Report DMCA

Goes above and beyond expectations !

Similar Questions
Hot Questions
Related Tags

Brown University

1271 Tutors

California Institute of Technology

2131 Tutors

Carnegie Mellon University

982 Tutors

Columbia University

1256 Tutors

Dartmouth University

2113 Tutors

Emory University

2279 Tutors

Harvard University

599 Tutors

Massachusetts Institute of Technology

2319 Tutors

New York University

1645 Tutors

Notre Dam University

1911 Tutors

Oklahoma University

2122 Tutors

Pennsylvania State University

932 Tutors

Princeton University

1211 Tutors

Stanford University

983 Tutors

University of California

1282 Tutors

Oxford University

123 Tutors

Yale University

2325 Tutors