A frisbee is thrown and released at a height of 3 feet. The height h in feet of the frisbee at time t in seconds is given by the formula h=t -0.099t^2+3. At what time will the height of the frisbee be 3 feet again?

velocity = 0 at h = 3ft

dh/dt =0

so 1- .198t =0

t = 1/0.198 = 5.05 sec

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