Algebra Word Problem

label Algebra
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The distance d in feet a bomb falls in t seconds is given by d=16t^2/1+0.06t . How many seconds are required for a bomb released at 15,000 feet to reach its target? 

May 14th, 2015

The distance d, in feet, a bomb falls in t seconds is given by d=16t%5E2%2F%281+%2B.06t%29How many seconds are required for a bomb released at 21,000 feet to reach its target? (If necessary, round your answer to two decimal places.) 
A) 1167.12 seconds
B) 185.76 seconds
C) 92.88 seconds
D) 2972.19 seconds 
d=16t^2/(1 +.06t)


21000(1+0.06t)=16t^2
21000+1260t-16t^2=0
4t^2-315t-5250=0
Graphing this I find the zero at 92.88 seconds.

May 14th, 2015

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