The distance d in feet a bomb falls in t seconds is given by d=16t^2/1+0.06t . How many seconds are required for a bomb released at 15,000 feet to reach its target?
16t^2/1+0.06t = 15000
16t^2 = 15000 + 900t
16t^2 - 900t - 15000 = 0
Use quadratic formula to solve:
t = 69.7 seconds
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