#15 2.09 Precalculus questions

label Mathematics
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schedule 1 Day
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May 14th, 2015

We can factor 2 out right away

2(x^4 - 8x^2 - 9)

When you have a problem like this, you can make a simple substituion:
x^2=y

This will make the problem:
2(y^2 -8y -9), a form youre probably familiar with already

2(y-9)(y+1)

Now we can make the substituion again
2(x^2 - 9)(x^2 + 1)

x^2 - 9 can be factored again to (x+3)(x-3)

Your final answer is:

2(x+3)(x-3)(x^2 + 1)

May 14th, 2015

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May 14th, 2015
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May 14th, 2015
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