We can factor 2 out right away
2(x^4 - 8x^2 - 9)
When you have a problem like this, you can make a simple substituion:
This will make the problem:
2(y^2 -8y -9), a form youre probably familiar with already
Now we can make the substituion again
2(x^2 - 9)(x^2 + 1)
x^2 - 9 can be factored again to (x+3)(x-3)
Your final answer is:
2(x+3)(x-3)(x^2 + 1)
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