We can factor 2 out right away 2(x^4 - 8x^2 - 9) When you have a problem like this, you can make a simple substituion: x^2=y This will make the problem: 2(y^2 -8y -9), a form youre probably familiar with already 2(y-9)(y+1) Now we can make the substituion again 2(x^2 - 9)(x^2 + 1) x^2 - 9 can be factored again to (x+3)(x-3) Your final answer is: 2(x+3)(x-3)(x^2 + 1)

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