e^(2x+3) - 3e^(x) + 2 = 0
will get back to you in a few minutes..... There is some problem in uploading the document.........................................................
e^(2x) - 3e^(x) + 2 = 0
put y = e^x
(y-3) (y-2) =0
y =3 or y =2
e^x = 3 or e^x =2
x = ln 3 or ln2
I am sorry please ignore the above
(y-1) (y-2) =0
y =1 or y =2
e^x = 1 or e^x =2
x = ln 1 or ln2
x =0 or ln2
Hey I just noted that there is some problem with the question. Please ignore my first two comments.
e^(2x+3) - 3e^(x) +2 =0 is not solvable.
Writing the power term in brackets
it has to be "-2"
e^(2x+3) - 3e^(x) - 2 =0 which can be simplified to
e^(2x)*e^(3) - 3 e^(x) - 2 = 0
e^(3) = 20 and e^(x) = y
it will become 20 y^(2) - 3y - 2 =0
Solving for y, you will get y = 0.4 as e^(x) cannot be a negative or an imaginary term
and x = -0.91629073187
Please confirm if the last term is -2 in the question.
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