#24 5.3.2 Precalculus questions

Mathematics
Tutor: None Selected Time limit: 1 Day

May 15th, 2015

Cos2x(2Cosx + 1) = 0

Now

Cos2x = 0    ,          2Cosx + 1 =0

2x = Cos^-1 (0)        ,          2Cosx = - 1

2x = π/2                  ,            Cosx = - 1/2

x = π/4                   ,                  x = Cos^-1 (- 1/2)

                                                 x = 2π/3

Hence     x = π/4     x = 2π/3

May 15th, 2015

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