#6 5.05 Precalculus questions

Mathematics
Tutor: None Selected Time limit: 1 Day

May 15th, 2015

sec (2theta) = 1/cos (2theta)

cos (2theta)==[1-tan^2 (theta)]/[1+tan^2 (theta)]

tan (theta) = 3/4

cos (2theta)=[1-9/16]/[1+9/16]=[7/16]/[25/16]=7/25

sec (2theta) = 1/cos (2theta)=1/[7/25]=25/7=3.57

May 15th, 2015

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May 15th, 2015
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