The tangent line to the graph of the function y=x^3 - 2x +1 are drawn at the points (-1,2) and (0,1) Find the x-coordinate of the intersection point of these two lines.

y=x^3-2x+1

dy/dx=3x2-2

gradient=1,and -2

y-2/x+1=1

y=x+3

y-1=-2x

y=-2x+1

x+3=-2x+1

x=-2/3

y=2 1/3

coordinates (-2/3,2 1/3)

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