Description
The tangent line to the graph of the function y=x^3 - 2x +1 are drawn at the points (-1,2) and (0,1) Find the x-coordinate of the intersection point of these two lines.
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Explanation & Answer
y=x^3-2x+1
dy/dx=3x2-2
gradient=1,and -2
y-2/x+1=1
y=x+3
y-1=-2x
y=-2x+1
x+3=-2x+1
x=-2/3
y=2 1/3
coordinates (-2/3,2 1/3)
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