2. Where is the vertex of the parabola?

y = x2 + 2x + 1

Above the x-axis

Below the x-axis

On the x-axis

On the y-axis

3. Use the discriminant to determine how many x-intercepts the graph of the equation has.

y = – 4x2 + 4x – 1

zero

one

two

three

4. In which direction does the parabola open?

y = 3x2 – 5x – 10

down

right

left

up

5. What are the x-intercepts of the quadratic function?

y = x2 – x – 2

2 and 1

–2 and 1

2 and –1

1

2. x-coordinate of the vertex is -b/2a = -2/2 = -1, y is 1-2+1=0.So on the x-axis.

3. Discriminant = b^2-4ac = 16-16 = 0.So one x-intercept (of multiplicity 2).

4. y=a*x^2+... then up or down. a=3>0 then up.

5. x-intercepts are where y=0. They are 2 and -1 (2^2-2-2=0 and (-1)^2-(-1)-2=0 ).

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up