#12 Precalculus questions

label Mathematics
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May 15th, 2015

sec(t) = 1/cos(t), tan(t) = sin(t)/cos(t).

So (sec(t)*sin(t))/tan(t) - 1 = [sin(t)/cos(t)]/[sin(t)/cos(t)] - 1 = 1 - 1 = 0.

The last variant.

May 15th, 2015

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May 15th, 2015
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May 15th, 2015
Sep 24th, 2017
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