Find the surface area of the right solid

Mathematics
Tutor: None Selected Time limit: 1 Day

May 15th, 2015

First we find the area of the base:

The square part is 10 x 10 = 100 cm^2,  the triangular part is 1/2(5)(2) = 5 cm^2

So, the area of the base is 100 + 5 = 105 cm^2

The top and bottom of the solid is 2(105) = 210 cm^2

Two sides of the solid are both: 10 x 12 = 120, so both together are 240 cm^2

Another side is: 15 x 12 = 180 cm^2

Another side is:  8 x 12 = 96 cm"2

The final side is: 5.4 x 12 = 64.8 cm^2

Total surface area is

210 + 240 + 180 + 96 + 64.8 = 790.8 cm^2

May 16th, 2015

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May 15th, 2015
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May 15th, 2015
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