Use natural logarithms to solve the equation.

Algebra
Tutor: None Selected Time limit: 1 Day

7e2x – 5 = 27


Round to the nearest thousandth
May 16th, 2015

7e^2x-5=27

7e^2x=27+5

7e^2x=32

e^2x=32/7

e^2x=

2x=ln(32/7)

x=0.760

May 16th, 2015

Thank you for taking the time to answer these for me. I need this to graduate

May 16th, 2015

do you need any explanation how to reach answer?

May 16th, 2015

What do you mean?

May 16th, 2015

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