What is the foci of graph

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qshragrf358

Mathematics

Description

What are the foci of the graph x^2/36-y^2/16=1

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Explanation & Answer

x^2/36-y^2/16=1

focus will be given bysqrt%2836-16%29

=sqrt+%2820%29

=-4.47 or 4.47

focus =(4.47,0) or (-4.47,0)




Anonymous
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