(y-k)^2 = 4p(x-h) (h,k) is the vertex

Vertex (0, 0), so h=0 and k=0

Focus (7, 0)

p is the distance between the vertex and the focus : (0,0) and (7,0) p = sqrt ( (0-7)^2 +(0-0)^2 ) = 7

so (y-0)^2 = 4*7*(x-0)

y^2=28x

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