Find the foci of the ellipse with the equation

Algebra
Tutor: None Selected Time limit: 1 Day

Find the foci of the ellipse with the equation x^2/16+y^2/25=1

May 16th, 2015

e= eccentricity of ellipse = focal distance/semi-major axis = sqrt(1-16/25)= sqrt(9/25)=3/5

semi-major axis = sqrt(25)=5 (along the y axis)

The ellipse is stretched vertically along the y-axis

focal distance from center of ellipse= 5*3/5=3

The locations of foci are then: (0,3), (0, -3)


May 16th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
May 16th, 2015
...
May 16th, 2015
Mar 25th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer