When does the particle have a displacement of +1 meter from its initial position
(at t = 0)?
4. Hot air balloon A is rising upward at a rate of 10.0 m/s. A passenger aboard balloon A observes balloon B going down at a relative rate of 12.5 m/s. What is the velocity of balloon B relative to the ground? Assume that up is positive.
3. Be careful with this question. Notice on the graph that the particle starts at a distance of -1 meters. To find the displacement of +1 meter from its initial position, you must find where the particle is at 0 meters.
t = 4.0 seconds
Va = velocity of hot air balloon A = 10.0 m/s
Vba = velocity of hot air balloon B relative to balloon A = 12.5 m/s
Vbg = velocity of hot air balloon B relative to ground = ?
Since balloon A sees balloon B traveling at a rate of 12.5 m/s when balloon A is traveling upward, we know that the velocity of balloon B will be less than 12.5m/s. We must take the difference between Va and Vba to determine Vbg:
Vbg = Va - Vba = 10.0m/s - 12.5m/s = -2.5m/s (negative velocity means balloon B is traveling downward)
Let me know if you have any questions! Hope this helps :)