Evaluate the function ƒ(x) = 6x - 5 at ƒ

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Question description

Evaluate the function ƒ(x) = 6x - 5 at ƒ(1)


Find all real values of x such that ƒ(x) = 0 for ƒ(x) = 42 - 6x


1 To evaluate a function, we: Multiply f times the given number or expression Substitute its variable with a given number or expression Multiply the variable times the given number or expression All of the answers are correct To visually determine if a graph represents a function or not, we can use: Vertical Line Test Horizontal Line Test Domain and Range Test There is no way to determine from a graph. The table below describes a function. Input Value Output Value 2001 2002 2003 2004 2005 30 60 30 50 40 True False Evaluate the function ƒ(x) = 6x - 5 at ƒ(1) 2 1 -1 0 2 What is the range of a function? Show your work Find all real values of x such that ƒ(x) = 0 for ƒ(x) = 42 - 6x 7 5 9 6 8 What is the domain of the function? The set of “x” values that will produce a “y” value The set of “y” values that will produce an “x” value All real numbers Impossible to be determined Find the zeroes of the function algebraically. Write the answer, if applicable, in fraction form. Show your work ƒ(x) = 2x2 - 3x -20 3 Find (ƒ+g)(x) for ƒ(x) = x+3, g(x) = x - 3 2x 3x -2x 2x+6 Find (ƒ-g)(x) for ƒ(x) = x + 6, g(x) = x - 6 2x - 12 12 2x - 6 2x + 12 Find (ƒg)(x) for: 7x3 + 6x2 7x3 - 6x2 7x2 - 6x3 7x2 + 6x3 4 Find ƒ ∘ g for: x2 (x - 5)2 (x + 5)2 x2 - 5 Select the correct description of right-hand and left-hand behavior of the graph of the polynomial function. Falls to the left, rises to the right. Falls to the left, falls to the right. Rises to the left, rises to the right. Rises to the left, falls to the right. Falls to the left. Describe the right-hand and the left-hand behavior of the graph of Because the degree is odd and the leading coefficient is positive, the graph falls to the left and rises to the right. Because the degree is odd and the leading coefficient is positive, the graph rises to the left and rises to the right. Because the degree is odd and the leading coefficient is positive, the graph falls to the left and falls to the right. Because the degree is odd and the leading coefficient is positive, the graph rises to the left and falls to the right. 5 Using an online calculator, sketch the graph of the function to find the zeroes of the polynomial. 0,2,3 0,2,-3 0,-2,3 1,2,3 Any non-zero number divided by zero is: Show your work Select the graph of the function and determine the zeros of the polynomial: f(x) = x2(x-6). Indicate which graph below is the correct one: 1st, 2nd, 3rd, or 4th. 6 7 The height, h(x), of a punted rugby ball is given by where x is the horizontal distance in feet from the point where the ball is punted. How far, horizontally, is the ball from the kicker when it is at its highest point? (Hint:Examine the vertex of this quadratic function) 28 feet 13 feet 18 feet 23 feet The profit P (in hundreds of dollars) that a company makes depends on the amount x (in hundreds of dollars) the company spends on advertising according to the model. P(x) = 230 + 40x - 0.5x2 What expenditure for advertising will yield a maximum profit? (Hint: Examine the vertex of this quadratic function) 40 0.5 230 20 The total revenue R earned per day (in dollars) from a pet-sitting service is given by R(p) = -10p2 + 130p where p is the price charged per pet (in dollars). Find the price that will yield a maximum revenue. $7.5 $6.5 $8.5 $10.5

Tutor Answer

vmohanakumar
School: University of Maryland

Attached. Let me know if you have any questions or concerns.

Is the relation a function?
y = x2 + 12x + 31
Question 1 options:
Yes
No

Question 2 (5 points)

Write the standard form of the equation of the circle with radius 7 and center at (0, 0).
Question 2 options:

x2 + y2 = 49
x2 + y2 = 14
x2 + y2 = 7
Save
Question 3 (5 points)

Convert the equation to the standard form for a hyperbola by completing the square on x and y.
x2 - y2 + 6x - 4y + 4 = 0
Question 3 options:
(x + 3)2 + (y + 2)2 = 1

-

=1

(x + 3)2 - (y + 2)2 = 1
(y + 3)2- (x + 2)2 = 1
Save
Question 4 (5 points)

Find the location of the center, vertices, and foci for the hyperbola described by the equation.

-

=1

Question 4 options:
Center: ( -4, 1); Vertices: ( -10, -1) and ( 2, -1); Foci: ( -4 Center: ( 4, -1); Vertices: ( -2, -1) and ( 10, -1); Foci:

Center: ( -4, 1); Vertices: ( -9, 1) and ( 3, 1); Foci: ( -3 +
Center: ( -4, 1); Vertices: ( -10, 1) and ( 2, 1); Foci:
(
Save
Question 5 (5 points)

, -1) and ( -4 +

, -1)

and

, 2) and ( 2 +
and

, 2)

Write the equation in terms of a rotated x'y'-system using θ, the angle of rotation. Write the equation
involving x' and y' in standard form. xy +16 = 0; θ = 45°
Question 5 options:

+

=1

y'2 = -32x'

-

=1

+

=1

Save
Question 6 (5 points)

Find the standard form of the equation of the ellipse and give the location of its foci.

Question 6 options:

+

=1

foci at (-7, 0) and ( 7, 0)

+

=1

foci at (-

-

, 0) and (

, 0)

, 0) and (

, 0)

, 0) and (

, 0)

=1

foci at (-

+
foci at (-

=1

Save
Question 7 (5 points)

Match the equation to the graph.
x2 = 7y
Question 7 options:

Save
Question 8 (5 points)

Convert the equation to the standard form for a hyperbola by completing...

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Anonymous
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