a) substituting the values we have;

3302=30(x^(4/5))*(y^(1/5))

finding the derivative then,

0=30(4/5)*(x^(-1/5))(y^(1/5))+30(x^(4/5))*(y^(-4/5))*y'. note: y'=dy/dx

making y' the subject then,

y'=(-4/5)*{[(x^(-1/5))*y(1/5)]/[x^(4/5)*y^(-4/5)]}

y'=(-4/5)*(y/x)

b) substituting (81,375 to the results of (a) then,

y'=(-4/5)*(81/375)

y'=(-0.8)*(0.216)

y'=-3.704

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