Elementary Algebra Question(30)

Algebra
Tutor: None Selected Time limit: 1 Day

Can I have help on the 30th question from this link please?

https://docs.google.com/file/d/0ByXp6Ibu-fCyOTBhMmE5MjgtN2U2Yy00YWI1LThmNDQtZjAzOWVmMTdmNjc1/edit?pli=1

May 18th, 2015

1.   50/2  -(5-11)^2

25 - (-6)^2 = 25-36 = -11  (Answer)

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May 18th, 2015

I only needed help just on the 30th question. The other problems I can do.

May 18th, 2015

ok please let me see

May 18th, 2015

Its fine. Thank you for helping out with the question. I'll be practicing it.

May 18th, 2015

Let the speed of Fright train is  x miles/hr than speed of passenger train will be = 2x miles/hr

Distance traveled in Fright train = 350 miles   hence travel time by fright train = distance/speed = 350/x hrs

Distance traveled in Passenger train = 700 miles, hence travel time by passenger train = distance/speed = 700/2x = 350/x hrs

since total travel time is 20 hrs therefore 

350/x + 350/x = 20

or 700/x = 20

solving we get , x = 700/20 = 35 miles/hrs

hence Average speed of Fright train = 35 mils/sec

& Passenger train = 2 * 35 = 70 miles /sec        (Answer)


May 18th, 2015

you can add me as your tutor ... if desire !!!!

May 18th, 2015

Sure I'll add you. Everyone's helpful in this website.

May 18th, 2015

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