Let P(x)=x^4-2x^3-24x^2+27x+108

determine all the zeros of p(x)

P(x)=(x-3)(x+4)(x^2-3x-9) =0

the slolution is

x=3

x=-4

x =-3/2*(sqrt(5)-1)

x= 3/4(sqrt(5)+1)

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