AP calculus

label Calculus
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x^3 and y = x.

May 18th, 2015

According to given question

y=x^3

y=x

By subtituting value of y

x^3=x

x^3-x=0

x(x^2-1)=0

so,x=0

x^2=1

x=1


By mid point rule of integration

A = ∫ (x³ -x) dx from 0 to 1

[x^4/4-m^2/2]-[x^4/4-m^2/2]  from 0 to 1

=-1/4+1/2

=-3/4 Answer


May 18th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
May 18th, 2015
...
May 18th, 2015
Oct 18th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer