Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x^3 and y = x.
According to given question
By subtituting value of y
By mid point rule of integration
A = ∫ (x³ -x) dx from 0 to 1
[x^4/4-m^2/2]-[x^4/4-m^2/2] from 0 to 1
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