Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x^3 and y = x.

According to given question

y=x^3

y=x

By subtituting value of y

x^3=x

x^3-x=0

x(x^2-1)=0

so,x=0

x^2=1

x=1

By mid point rule of integration

A = ∫ (x³ -x) dx from 0 to 1

[x^4/4-m^2/2]-[x^4/4-m^2/2] from 0 to 1

=-1/4+1/2

=-3/4 Answer

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