Can I get help on the 10th question from this link please?

https://docs.google.com/file/d/0ByXp6Ibu-fCyOTBhMmE5MjgtN2U2Yy00YWI1LThmNDQtZjAzOWVmMTdmNjc1/edit?pli=1

Let's first write the equation 2x+3y=24 in slope intercept form

2x+3y=24 <=> 3y=24-2x <=> y=-2/3x+8

The slope of this line is -2/3

The equation of the line perpendicular to the last one is y=mx+b

As these 2 lines are perpendicular, the product of their slopes equals -1 so m*(-2/3)=-1 so m=3/2

So we have that y=3/2x+b or this line is passing through (-6;2) so 2=3/2*(-6)=b and finally b=11

Finally the equation of the line is y=3/2x+11

Good luck !!!

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