Help Me WITH ALGEBRA

Algebra
Tutor: None Selected Time limit: 1 Day

Solve each equation, if possible. Write irrational numbers in simplest radical form. Describe the strategy you used to get your solution and tell why you chose that strategy.

  1. x^2+4=0
  2.x^2-6x+1=0
May 18th, 2015

uadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 2x%5E2%2B-6x%2B1+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4acb%5E2-4ac=%28-6%29%5E2-4%2A2%2A1=28.

Discriminant d=28 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--6%2B-sqrt%28+28+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-6%29%2Bsqrt%28+28+%29%29%2F2%5C2+=+2.8228756555323
x%5B2%5D+=+%28-%28-6%29-sqrt%28+28+%29%29%2F2%5C2+=+0.177124344467705

Quadratic expression 2x%5E2%2B-6x%2B1 can be factored:
2x%5E2%2B-6x%2B1+=+2%28x-2.8228756555323%29%2A%28x-0.177124344467705%29
Again, the answer is: 2.8228756555323, 0.177124344467705. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-6%2Ax%2B1+%29

1= answer

Given is x^2 - 4 = 0 
-> x^2 - 2^2 = 0 ( 4 = 2^2 ) 


-> (x-2).(x+2) = 0 ( x^2 - a^2 = (x-a).(x+a) ) 
-> x-2 = 0 or x+2 = 0 
-> x = 2 or x = -2

May 18th, 2015

what about answer 2???

May 18th, 2015

1= answer

Given is x^2 - 4 = 0 
-> x^2 - 2^2 = 0 ( 4 = 2^2 ) 


-> (x-2).(x+2) = 0 ( x^2 - a^2 = (x-a).(x+a) ) 
-> x-2 = 0 or x+2 = 0 
-> x = 2 or x = -2


May 18th, 2015

x=-0.177243....................is your final answer

May 18th, 2015

what about 1??

May 18th, 2015

> x = 2 or x = -2

is your answer..............x=+-2

May 18th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
May 18th, 2015
...
May 18th, 2015
Dec 10th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer