A person weighs 764 N on the surface of Earth and 5320 N on the surface of anoth

Physics
Tutor: None Selected Time limit: 1 Day

6. A person weighs 764 N on the surface of Earth and 5320 N on the surface of another planet. What is the acceleration due to gravity on the other planet? 

7. A person is standing motionless between a straight highway and an airport runway. A truck drives by the person at constant speed, while an airplane accelerates down the runway for take off. Of the person, truck, and airplane, which are an inertial frame of reference?

May 18th, 2015

6)

First, the mass on earth: 764/9.8ms^-2 = 75.6kg

f=mass*acceleration, so

acceleration=force/mass

a = 5320N/75.6kg = 70.36 m/s^2

7)

Trick question: Both the person AND the truck are inertial frames of reference. The person because they are standing still, and the truck because it is moving at a constant velocity.

The plane IS NOT because it is accelerating :)


May 18th, 2015

the first one its not in my answer choices. 

May 18th, 2015

Are the units of the answers in the same units of my response?

Also, the only way to measure this otherwise is to know the radius of the other planet-- is that a given value anywhere in the problem?

May 18th, 2015

amm.. nope :/ 

a. 78.4 m/s2

b. 49.8 m/s2

c. 59.3 m/s2

d. 68.2 m/s2


the closest one is d 


May 18th, 2015

Ah ha! OK. They took the tricky route. Let me write up the right response.

May 18th, 2015

okay c:

May 18th, 2015

My answer was correct: It's 68.2 m/s2. 

The other way you could easily do this is to set up a proportion:

If a g of 9.8m/s2 gives 764N, what's the ratio?

9.8m/s2/764=? g/5320

? g = (9.8*5320)/764= 68.2 m/s2 :)

The difference is that I had my calculator set to .1 decimal places. I just redid this calculation in Excel. Sig figs, they'll get you every time.

Please let me know

May 18th, 2015

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