If 1.0 gram of hydrogen reacts with 19.0 grams of fluorine, then what is the percent by mass of fluorine in the compound that is formed?
H2 + F2 --> 2(HF)
Number of moles of hydrogen:
n(H2) = m / M = 1 / 2.016 = 0.49603
Number of moles of compound (HF):
n(HF) = 2 x n(H2) = 0.99206
Mass of compound:
m = n x M = 0.99206 x 20.006 = 19.84715
Percentage by mass:
%(H2) = pure / impure x 100 = 1 / 19.84715 x 100 = 5.0385
Give answer in the same amount of significant figures as question (2):
The compound is 5.0% hydrogen.
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?