##### A 1200.0-kg car is traveling at 19 m/s . The driver suddenly slams on the brake

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4. A  1200.0-kg car is traveling at 19 m/s . The driver suddenly slams on the brakes and skids to a stop. The coefficient of kinetic friction between the tires and the road is 0.80. For what length of time is the car skidding?

5. An object attached to a spring is being pulled across a flat frictionless surface. The spring constant is 48 N/M, the object is accelerating at 1.1 m/s², and the mass of the object is 38 kg. What distance is the spring stretched?

May 18th, 2015

energy equation which is broken down to (change in PE+KE)=nonconservative forces*distance(which is also energy)=>1/2mv^2=Fd where F is a force and d is the distance F would be friction force which is normal force (force of gravity in this case) * coefficient of friction(mu).... simplified (1/2v^2)/(mu*g)=d=23.023meters

Same idea as before

F=ma; Fd=1/2kx^2 where d is the distance the force is acting over and x is the distance stretched (which in this case x=d) ... simplified 2ma/k=x=.871meters

May 18th, 2015

number 4

1.7 s

2.9 s

2.4 s

3.9 s

has to b one of those

May 18th, 2015

F=ma=mu*mg...a=mu*g Vf = Vo+at...simplified Vo/a=t=2.42secs

May 18th, 2015

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May 18th, 2015
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May 18th, 2015
Oct 19th, 2017
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